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The equlibrium surface or tide potential

If we apply the conditions required for static equlibrium of the ocean in the presence of the tide producing forces at a given instant, it is possible to evaluate the equilibrium form of the surface of an ocean covering the entire earth. The deviation of this imaginary equilibrium form under the influence of the frozen tide producing forces from the equlibrium form under the influence of gravity alone represents, in effect, the potential of the tide producing force.

If we apply the conditions required for static equilibrium of the ocean in the presence of the tide-producing forces at any given instant, it is possible to evaluate the equilibrium form of the surface of an ocean covering the entire earth. The deviation of this imaginary equilibrium form under the influence of the ``frozen'' tide-producing forces from the equilibrium form under the influence of gravity alone represents in effect the potential of the tide-producing forces.

Let represent the vertical displacement of sea level from the level surface which is defined by gravity alone. Under conditions of static equilibrium, the sea surface must be normal to the effective gravity which includes the tide-producing force.

From Fig. 2.04-6 is is evidence that at a given position of the surface

The distance x is to be measured along a great circle path which lies in the plane which, if extended, passes through the center of the body producing the tidal force (Fig. 2.04-4a). Thus, if we take the reference surface as a sphere then

Consequently, the potential associated with the lunar tide-producing force (Eq. 50b) is governed by the equation

the negative sign being required since the force is directed opposite to the direction of increasing . Integrating this gives

The constant of integration must be chosen such that no change in the volume of water results from the tidal distortion. This requires that C be unity such that

It is interesting to note that this has the same form as the vertical component of the tidal force (Eq. 50a). In fact,

even though has nothing to do with actually producing the distortion. The maximum value of is 35.4 cm and occurs at values of equal to 0 and (i.e. directly under the moon and opposite). The minimum value of occurs for equal to or and equals -17.7 cm. Thus, the range of the tidal distortion is 53.1 cm. The form of the tidal equilibrium surface is a prolate spheriod of revolution whose axis of symmetry is always directed towards the moon. This is illustrated in Fig. 2.04-7. The value of is zero for .

The potential or equilibrium distortion associated with the solar tide-producing forces is given by

The range of is 24.4 cm. At the times of the solar and lunar eclipses the total potential distortion due to the combined action of the sun and the moon acquires the maximum range of 77.5 cm (2.54 feet). At the times of new moon and full moon, which occur about every 14 days, the combined tidal potential approaches this extreme condition but the effect is generally somewhat less because of the inclination of the moon's orbit to the earth/sun ecliptic plane.

For a perspective diagram of the distribution of the horizontal tide-producing forces reference is made to (), Fig. 138B, p. 547.


next up previous contents
Next: The time variation of Up: Tidal forces Previous: Tidal forces associated with

Steve Baum
Mon Dec 1 08:50:29 CST 1997