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Viscous stresses

Following Stokes and others it will be presumed that the viscous stress tensor can be expressed as a linear combination of the deformation tensor and the divergence as follows

This combination of terms satisfies the requirement thta be symmetrical, i.e. , since both the deformation and the unit tensor are symmetrical. It will be recalled that the Kronecker delta is defined by

For the case of simple shear where v = w = 0 and u = u(z), the stresses reduce to

all all other stresses are zero. This is the law commonly applied in the case of flow in a thin lamina of fluid contained between two flat plates. For radially symmetric flow in a circular tube where u = u(r), the analogous special case for the stresses is

with all other stresses being zero (a x directed along the axis of the tube).

Another special case of (5.03-1) is for plane acoustical waves of the simplest type where v = w = 0, u = u(x,t). In this case

and all other stresses are zero. This shows that a different coefficient governs for the stress related to pure bulk deformation as compared with the stress related to pure shear. There is empirical evidence to support this result, and hence justifies the inclusion of the special term for divergence in the assumed general expression (5.03-1).

The general stress from (5.03-1) when written out in full are

The coefficents and , which will be referred to as the kinematic shear viscosity and the kinematic bulk viscosity, respectively, have the dimensions of length times velocity like . The value of is not completely independent of but is restricted to certain values depending on the value of . One possible relation between and was given by Navier and Stokes, but Eckart has proven that the Navier-Stokes relation is only a limiting case of a more general relation (as Lamb already implied in one of his cautious footnotes, p. 575). The proof given below follows that of Eckart and is based upon the second law of thermodynamics.

For convenience, the second law is restated as

In the discussion of the previous sections of this chapter we have considered a which depends upon and a which depends essentially upon , and consequently the term involving these quantities in (VI) must be independently positive or at least zero since it is independent of the other quantities. This is also true of the term involving the viscous stress, since by (5.03-1) no dependence on the gradients of or T has been assumed. The situation in this case, however, is complicated by the fact that the term in itself involves six different variables. That is, the statement

when written out in full, employing the relation (5.03-1), becomes

where the subscripts are used as an abbreviation of the appropriate partial derivatives (i.e. , etc.). This relation involves a sum of squares and will certainly be positive if both and are positive. However, the latter restriction is too severe, for it is possible for to be negative and still not violate the inequality expressed in (5.03-8). The reason for this lies in the fact that in the first line of (5.03-8) there are four squares but only three different variables. It is known from the theory of quadratic functions that the above sum of four squares can be reduced to a sum of three squares of functions which are simple linear combinations of the three variables. In the second line of (5.03-8) we already have three squares involving three variables, and this can be reduced no further. Furthermore, since the three variables in the second line (the three components of shear deformation) are independent of the three variables in the first line, it follows that the second line must satisfy the inequality independently. Therefore, we obtain as the first result , which agrees with empirical findings.

To find the restriction on we must first reduce the expression

to the sum of three squares. Expanding the last term and rearranging gives

This suggests the possible form

Expanding this yields

which, when compared with (5.03-10), gives five equations for the five unknown coefficients in (5.03-11). The resulting values are

In order to satisfy the required inequality it is therefore necessary that the coefficients , and each be positive or at least zero. This requirement is met if

for it is readily shown that the terms and are positive under this condition. Thus, in summary, it has been shown that for the assumed form for as given by (5.03-2) the coefficients are restricted by the conditions

in order that the second law of thermodynamics be satisfied. The limiting condition on , that , represents the celebrated Navier-Stookes relation, which was arrived at by a different line of reasoning (Lamb (1945), p. 574). As for empirical support for the more general result, the following quotation is taken from (), p. 87: ``In the last ten years, experiments on the absorption of sound have suggested that may be positive, and even be greater than , by as much as a factor of ten in some liquids. In the case of water, the factor appears to be about +1.''

In the equation of motion (III-1) or (III-3) the viscous stress enters in the form

This represents the contribution to the time rate of change in momentum of a unit volume of fluid due to viscous stresses or, in other words, the viscous force per unit volume. Employing Eq. (5.03-1) we find that

which can also be written in the more familiar vector notation as

where is the Laplacian operator. Another form can be shown to be

The first of these equations is useful in dealing with divergenceless motion, in which case the viscous force per unit volume reduces to ; while for irrotational motion the second form shows that the viscous force is . Note that from the conditions (5.03-15)

In the case of water is nearly the same as as noted earlier, hence

which differ vastly from the limiting Navier-Stokes relations.

Eckart has pointed out a somewhat paradoxical situation which arises in connection with Laplacian flow for which both and are zero, resulting in the condition that satisfies the Laplacian equation

In this case the viscous force vanishes identically. However, the stresses are not zero and lead to dissipation of kinetic energy into internal energy since the term

as long as differs from zero. The theory of gravity waves and ripples is based almost exclusively on the assumption of Laplacian flow and one may well ask how a free wave train of permanent form can exist, as is possible for Laplacian motion, when the kinetic energy of the system is being reduced through dissipation. Reference to Eq. (III-4) suggests that this is possible if the work is done on the fluid by the surface stresses. In fact, the vanishing of implies that

under conditions of Laplacian flow. However, this contradicts the statement that the waves are free (i.e., not forced). Thus there are still some paradoxical elements that require further study. The problem is perhaps most significant in connectino with the small capillary waves or ripples which evidently are subject to considerable damping and therefore may possess significant vorticity, contrary to the usual theories. Here is an inviting problem awaiting some student to explore! It derives its importance from the fact that the upper end of the frequency spectrum of surface wave motion, e.g. ripples, has been shown by recent studies of () to be a vital connecting link in the mechanism of energy transfer from air to water. The problem of generation, maintenance and decay of such waves is therefore a significant one from the practical standpoint.


next up previous contents
Next: Diffusion-drag theory Up: Some Special Laws of Previous: Diffusion

Steve Baum
Mon Dec 1 08:50:29 CST 1997